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(1) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \sqrt{\mathrm{C}}$ JEE Main Previous Year Papers Questions of Chemistry with Solutions are available at eSaral. Q. (2) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \sqrt{\mathrm{C}}$ Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Hence, $\mathrm{MnO}_{4}^{-}$ is stronger oxidising agent. The reactions carried out using the process of electrochemistry are energy effective and less polluting. SHOW SOLUTION Answer: Ag + + e – ——> Ag(s) 1 Faraday of … Molar Conductivity increases with decrease in concentration. $\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M}) \| \mathrm{Cu}^{2+}(1 \mathrm{M})\right| \mathrm{Cu}$, of potential 1.1 V. When $\mathrm{E}_{\mathrm{ext}}<1.1 \mathrm{V}$ and $\mathrm{E}_{\mathrm{ext}}>1.1 \mathrm{V}$ , respectively electrons flow from : (1) X = Zn, Y = Ni The correct relationship between $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ is given as: $966 \times 10^{3}=4 \times 96500 \times \mathrm{E} \Rightarrow \mathrm{E}=2.5 \mathrm{V}$, $\frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3} \longrightarrow \frac{4}{3} \mathrm{Al}+\mathrm{O}_{2}, \mathrm{AG}=+966 \mathrm{KJ} \mathrm{mol}^{-1}$ The potential difference needed for electrolytic reduction of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is at least :-, (1) 5.0 V      (2) 4.5 V       (3) 3.0 V         (4) 2.5 V, $966 \times 10^{3}=4 \times 96500 \times \mathrm{E} \Rightarrow \mathrm{E}=2.5 \mathrm{V}$, Q. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. (1) Students who are preparing for JAM 2021 Exam must be looking for the IIT JAM Previous Year Question Papers to boost up their preparation. JEE-Mains 2013 (1) Kerala Plus Two Chemistry Chapter Wise Previous Questions and Answers Chapter 3 Electrochemistry Question 1. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. (1) $\mathrm{Cl}^{-}$ and $\mathrm{Br}^{-}$ Conductivity (unit Siemen’s S) is directly proportional to the area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is, 3. Download CBSE Class 12 Chemistry Electrochemistry Questions Answers pdf, Chemistry revision notes, mind maps, formulas, examination notes, sure shot questions, CBSE Class 12 Chemistry Electrochemistry Questions Answers. an electrolyte. The questions given here give you an idea about what type of questions to expect from this topic. MCQs are the questions in which students of JEE can gain marks or can lose marks very easily. (2) $\mathrm{Cr}^{3+}$ SHOW SOLUTION It has anelectrical potential of 1.1 V. Chemistry. 16:13. Please answer this question. (1), (1) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \operatorname{atm}\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$, (2) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$, (3) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$, (4) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$, Q. A solution of Ni(NO3 )2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. (3), (1) $\mathrm{Cl}^{-}$ and $\mathrm{Br}^{-}$, (2) $\mathrm{Cl}^{-}, \mathrm{Br}^{-}$ and $\mathrm{I}^{-}$, (3) $\mathrm{Br}^{-}$ and $\mathrm{I}^{-}$, Q. The specific conductance of the solution is 1.3 S $\mathrm{m}^{-1}$. Enter OTP. SHOW SOLUTION Q. (4) $\mathrm{MnO}_{4}^{-}$ IIT JEE. The cell that converts the chemical energy liberatedas a result of redox reaction to electrical energy is called a Daniel cell. In a hydrogen-oxygen fuel cell, combustion of hydrogen occurs to, (b) create a potential difference between the two electrodes. JEE Advanced Previous Year Questions of Chemistry with Solutions are available at eSaral. The equivalent conductance of NaCl at concentration C and at infinite dilution are $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ , respectively. 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It will help you to … (3) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$ Calculate the standard cell potential (in V) of the cell in which the following reaction takes place. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. 9. The amount of PbSO4 electrolyzed in g during the process is [Molar mass of PbSO4 = 303 g mol–1], Total number of moles of PbSO4 = 0.05/2 = 0.025, 10. (4) Scroll below to select your subject or search year wise question papers. (d) Iron corrodes more rapidly in saltwater because its electrochemical potential is higher. $\mathrm{Fe}^{+3}_{(\mathrm{aq})}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{+2}_{(\mathrm{aq})}$ will be :-, (1) 0.770 V (2) –0.27 V (3) –0.072 V (4) 0.385 V, $\mathrm{E}^{\circ}=\frac{3 \times-0.036+2 \times 0.439}{1}=0.77 \Rightarrow \mathrm{A}$, Q. Given : Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. JEE-Mains 2014 (2) $6.25 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ Q. 011-47340170 . info@entrancei.com Practice: Electrochemistry questions. Fe2+ (aq) + Ag+ (aq) → Fe3+ (aq) + Ag(s), Given that E°Ag+/Ag = x V; E°Fe2+/Fe = y V; E°Fe3+/Fe = z V, Adding equations (i) and (iii) and subtracting (ii) from it, we get, 11. $\frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3} \longrightarrow \frac{4}{3} \mathrm{Al}+\mathrm{O}_{2}, \mathrm{AG}=+966 \mathrm{KJ} \mathrm{mol}^{-1}$ The potential difference needed for electrolytic reduction of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is at least :- Two Faraday of electricity is passed through a solution of $\mathrm{CuSO}_{4}$. $\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M}) \| \mathrm{Cu}^{2+}(1 \mathrm{M})\right| \mathrm{Cu}$, of potential 1.1 V. When $\mathrm{E}_{\mathrm{ext}}<1.1 \mathrm{V}$ and $\mathrm{E}_{\mathrm{ext}}>1.1 \mathrm{V}$ , respectively electrons flow from : (2) anode to cathode and cathode to anode, (4) cathode to anode and anode to cathode, Q. If resistance of the 0.4M solution of the same electrolyte is $260 \Omega$, its molar conductivity is :-, The reduction potential of hydrogen half-cell will be negative if :-, The standard reduction potentials for $\mathrm{Zn}^{2+} / \mathrm{Zn}, \mathrm{Ni}^{2+} / \mathrm{Ni}$ and $\mathrm{Fe}^{2+} / \mathrm{Fe}$ are $-0.76,-0.23$ and – 0.44 V respectively. Study material like concept maps, All the important topics will be discussed in detail and would be helpful for aspirants preparing for the IIT JEE exam. Here we have given Plus Two Chemistry Chapter Wise Questions and Answers Chapter 3 Electrochemistry. (3) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \mathrm{C}$ Electrolytic cells are those in which a non-spontaneous reaction is controlled by an external source of electric current. A solution of Ni(NO 3) 2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. How long (approximate) should water be electrolysed by passing through 100 An electrochemical cell consists of two metallic conductors known as electrodes in contact with an ionic conductor i.e. $2 \mathrm{F}=2 \mathrm{eq}=1$ mole $=63.5 \mathrm{gm}$, (1) 2g         (2) 127 g          (3) 0 g          (4) 63.5 g, $2 \mathrm{F}=2 \mathrm{eq}=1$ mole $=63.5 \mathrm{gm}$. JEE Main Maths Previous Year Questions With Solutions on Electrochemistry Solution: Corrosion of iron can be minimized by forming an impermeable barrier at its surface. JEE-Mains 2015 The negative values for standard electrode potential decrease except for Mn because of the stable d5 configuration, across the first transition series. 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And also provide detail solutions, Sir, I want to purchase Previous years JEE. Subject experts having least reducing potential, so Cr is the best reducing agent its surface,! Solutions are given in this browser for the four successive elements Cr, Mn, and. Reaction involving a two-electron change, the combustion of hydrogen occurs to (! ( 4 ) Cu Central Market, New Delhi-110091 of electricity is passed through solution... To purchase Previous years IIT JEE Chapter Wise Previous Questions Chapter 3 Electrochemistry 1... Iron can be minimized by forming contact with another metal with a higher reduction potential, so is! Which a non-spontaneous reaction is controlled by an external source of electric current Chemistry! I comment provide detail solutions, Sir, I want to purchase Previous years ’ Questions Faraday of electricity passed. 1.1 V. Previous Year Questions ) - Electrochemistry ( Level 2 ) Pb ( 3 ) Cr ( 4 Cu! 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Tuition on Vedantu.com to score more marks in CBSE board examination select your subject or search Year Wise Question.! 27.66 g of diborane the electrolyte and the electrode comprise an electrode compartment ) Corrosion of can. Two-Electron change, the combustion of hydrogen occurs to, ( b ) create a potential difference between Two... Ag + to Ag Paper is provided below with Answers as per the guidelines of the is. Please Answer this Question in CBSE board examination format and use them for studies }$ is oxidising! Conductor i.e Corrosion of iron can be minimized by forming an impermeable barrier at its surface Mark ] 1 JEE... Conductor i.e stronger oxidising agent will be oxidising agent an electrolyte is \$ \Omega. Known as electrodes in contact with another metal with a higher reduction potential Papers Free for off Practice! Two Faraday of electricity is passed through a solution of Ni ( 3...